1280 Students and Examinations

table of content

1280 Students and Examinations

To correctly list all students and their examination records, including subjects they did not take, we need to generate all possible student-subject combinations and count the number of exams taken for each.

Approach

  1. Use a CROSS JOIN between Students and Subjects:
    • This ensures that every student is paired with every possible subject.
    • This step is necessary because if a subject has no examination records in Examinations, it would be missing from the output.
    FROM Students AS s
    CROSS JOIN Subjects AS sub
    
  2. Perform a LEFT JOIN with Examinations:
    • This allows us to retain all student-subject combinations while bringing in exam records where available.
    LEFT JOIN Examinations AS e
    ON s.student_id = e.student_id AND sub.subject_name = e.subject_name
    
  3. Use GROUP BY to count the number of exams taken:
    • If a student has multiple records for the same subject, they will be counted.
    • If no exams were taken for a subject, the count will be 0.
    GROUP BY s.student_id, s.student_name, sub.subject_name
    

Conclusion

This method ensures that:

  • All students and subjects are represented in the output.
  • Subjects with no exams are correctly displayed with a count of 0.
  • Multiple exam records for a subject are aggregated properly.

This approach guarantees an accurate representation of student examination participation. imgimgimg