1280 Students and Examinations
To correctly list all students and their examination records, including subjects they did not take, we need to generate all possible student-subject combinations and count the number of exams taken for each.
Approach
- Use a
CROSS JOINbetweenStudentsandSubjects:- This ensures that every student is paired with every possible subject.
- This step is necessary because if a subject has no examination records in
Examinations, it would be missing from the output.
FROM Students AS s CROSS JOIN Subjects AS sub - Perform a
LEFT JOINwithExaminations:- This allows us to retain all student-subject combinations while bringing in exam records where available.
LEFT JOIN Examinations AS e ON s.student_id = e.student_id AND sub.subject_name = e.subject_name - Use
GROUP BYto count the number of exams taken:- If a student has multiple records for the same subject, they will be counted.
- If no exams were taken for a subject, the count will be
0.
GROUP BY s.student_id, s.student_name, sub.subject_name
Conclusion
This method ensures that:
- All students and subjects are represented in the output.
- Subjects with no exams are correctly displayed with a count of
0. - Multiple exam records for a subject are aggregated properly.
This approach guarantees an accurate representation of student examination participation. 

